(3/X+20)-(4/X-20)=4X/X^2-400

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Solution for (3/X+20)-(4/X-20)=4X/X^2-400 equation: 


D( X )

X = 0

X^2 = 0

X = 0

X = 0

X^2 = 0

X^2 = 0

1*X^2 = 0 // : 1

X^2 = 0

X = 0

X in (-oo:0) U (0:+oo)

3/X-(4/X)+20+20 = (4*X)/(X^2)-400 // - (4*X)/(X^2)-400

3/X-(4/X)-((4*X)/(X^2))+20+20+400 = 0

3/X-4*X^-1-4*X^-1+20+20+400 = 0

-5*X^-1 = -440 // : -5

X^-1 = 88

-1 < 0

1/(X^1) = 88 // * X^1

1 = 88*X^1 // : 88

1/88 = X^1

X = 1/88

X = 1/88

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